Mercurial > hg > truffle
annotate src/share/vm/utilities/intHisto.hpp @ 1721:413ad0331a0c
6977924: Changes for 6975078 produce build error with certain gcc versions
Summary: The changes introduced for 6975078 assign badHeapOopVal to the _allocation field in the ResourceObj class. In 32 bit linux builds with certain versions of gcc this assignment will be flagged as an error while compiling allocation.cpp. In 32 bit builds the constant value badHeapOopVal (which is cast to an intptr_t) is negative. The _allocation field is typed as an unsigned intptr_t and gcc catches this as an error.
Reviewed-by: jcoomes, ysr, phh
| author | johnc |
|---|---|
| date | Wed, 18 Aug 2010 10:59:06 -0700 |
| parents | c18cbe5936b8 |
| children | f95d63e2154a |
| rev | line source |
|---|---|
| 342 | 1 /* |
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2 * Copyright (c) 2001, 2007, Oracle and/or its affiliates. All rights reserved. |
| 342 | 3 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. |
| 4 * | |
| 5 * This code is free software; you can redistribute it and/or modify it | |
| 6 * under the terms of the GNU General Public License version 2 only, as | |
| 7 * published by the Free Software Foundation. | |
| 8 * | |
| 9 * This code is distributed in the hope that it will be useful, but WITHOUT | |
| 10 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or | |
| 11 * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License | |
| 12 * version 2 for more details (a copy is included in the LICENSE file that | |
| 13 * accompanied this code). | |
| 14 * | |
| 15 * You should have received a copy of the GNU General Public License version | |
| 16 * 2 along with this work; if not, write to the Free Software Foundation, | |
| 17 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. | |
| 18 * | |
|
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19 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA |
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20 * or visit www.oracle.com if you need additional information or have any |
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21 * questions. |
| 342 | 22 * |
| 23 */ | |
| 24 | |
| 25 // This class implements a simple histogram. | |
| 26 | |
| 27 // A histogram summarizes a series of "measurements", each of which is | |
| 28 // assumed (required in this implementation) to have an outcome that is a | |
| 29 // non-negative integer. The histogram efficiently maps measurement outcomes | |
| 30 // to the number of measurements had that outcome. | |
| 31 | |
| 32 // To print the results, invoke print() on your Histogram*. | |
| 33 | |
| 34 // Note: there is already an existing "Histogram" class, in file | |
| 35 // histogram.{hpp,cpp}, but to my mind that's not a histogram, it's a table | |
| 36 // mapping strings to counts. To be a histogram (IMHO) it needs to map | |
| 37 // numbers (in fact, integers) to number of occurrences of that number. | |
| 38 | |
| 39 // ysr: (i am not sure i agree with the above note.) i suspect we want to have a | |
| 40 // histogram template that will map an arbitrary type (with a defined order | |
| 41 // relation) to a count. | |
| 42 | |
| 43 | |
| 44 class IntHistogram : public CHeapObj { | |
| 45 protected: | |
| 46 int _max; | |
| 47 int _tot; | |
| 48 GrowableArray<int>* _elements; | |
| 49 | |
| 50 public: | |
| 51 // Create a new, empty table. "est" is an estimate of the maximum outcome | |
| 52 // that will be added, and "max" is an outcome such that all outcomes at | |
| 53 // least that large will be bundled with it. | |
| 54 IntHistogram(int est, int max); | |
| 55 // Add a measurement with the given outcome to the sequence. | |
| 56 void add_entry(int outcome); | |
| 57 // Return the number of entries recorded so far with the given outcome. | |
| 58 int entries_for_outcome(int outcome); | |
| 59 // Return the total number of entries recorded so far. | |
| 60 int total_entries() { return _tot; } | |
| 61 // Return the number of entries recorded so far with the given outcome as | |
| 62 // a fraction of the total number recorded so far. | |
| 63 double fraction_for_outcome(int outcome) { | |
| 64 return | |
| 65 (double)entries_for_outcome(outcome)/ | |
| 66 (double)total_entries(); | |
| 67 } | |
| 68 // Print the histogram on the given output stream. | |
| 69 void print_on(outputStream* st) const; | |
| 70 }; |